CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

∫dx1+3sin⁡2x=\int\frac{dx}{1+3\sin^2x}= (a) 13tan⁡−1(3tan⁡2x)+C\frac{1}{3}\tan^{-1}(3\tan^2x)+C (b) 12tan⁡−1(2tan⁡x)+C\frac{1}{2}\tan^{-1}(2\tan x)+C (c) tan⁡−1(tan⁡x)+C\tan^{-1}(\tan x)+C (d) None of these

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