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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
1
x
2
(
x
4
+
1
)
3
/
4
d
x
\int \frac{1}{x^2 (x^4 + 1)^{3/4}}\,dx
∫
x
2
(
x
4
+
1
)
3/4
1
d
x
is equal to (a)
(
1
+
1
x
4
)
1
/
4
+
c
\left(1 + \frac{1}{x^4}\right)^{1/4} + c
(
1
+
x
4
1
)
1/4
+
c
(b)
(
x
4
+
1
)
1
/
4
+
c
(x^4 + 1)^{1/4} + c
(
x
4
+
1
)
1/4
+
c
(c)
(
1
−
1
x
4
)
1
/
4
+
c
\left(1 - \frac{1}{x^4}\right)^{1/4} + c
(
1
−
x
4
1
)
1/4
+
c
(d)
−
(
1
+
1
x
4
)
1
/
4
+
c
-\left(1 + \frac{1}{x^4}\right)^{1/4} + c
−
(
1
+
x
4
1
)
1/4
+
c
Related theory
Integration Techniques
Integration by Substitution
Integrals
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