Prove that (B-C) B C + (C-A) C A + (A-B) A B = 0

MATHEMATICS · Subjective · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

Prove that sin⁡(B−C)cos⁡Bcos⁡C+sin⁡(C−A)cos⁡Ccos⁡A+sin⁡(A−B)cos⁡Acos⁡B=0\frac{\sin(B-C)}{\cos B \cos C} + \frac{\sin(C-A)}{\cos C \cos A} + \frac{\sin(A-B)}{\cos A \cos B} = 0

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