In a Young's double slit experiment with light of wavelength λ, the separation of slits is d and distance of screen is D such that D≫d≫λ. If the fringe width is β, the distance from point of maximum intensity to the point where intensity falls to half of maximum intensity on either side is:
(1) 6β
(2) 3β
(3) 4β
(4) 2β