In a Young's double slit experiment with light of wavelength

PHYSICS · Single correct · CBSE · Physics · Wave Optics · Wave Optics

Problem

In a Young's double slit experiment with light of wavelength λ\lambda, the separation of slits is dd and distance of screen is DD such that D≫d≫λD \gg d \gg \lambda. If the fringe width is β\beta, the distance from point of maximum intensity to the point where intensity falls to half of maximum intensity on either side is: (1) β6\frac{\beta}{6} (2) β3\frac{\beta}{3} (3) β4\frac{\beta}{4} (4) β2\frac{\beta}{2}

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