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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
sin
x
d
x
a
2
+
b
2
cos
2
x
=
\int \frac{\sin x\,dx}{a^2 + b^2\cos^2 x} =
∫
a
2
+
b
2
c
o
s
2
x
s
i
n
x
d
x
=
(A)
log
(
a
2
+
b
2
cos
2
x
)
+
c
\log(a^2 + b^2\cos^2 x) + c
lo
g
(
a
2
+
b
2
cos
2
x
)
+
c
(B)
1
a
b
tan
−
1
(
a
cos
x
b
)
+
c
\frac{1}{ab}\tan^{-1}\left(\frac{a\cos x}{b}\right) + c
ab
1
tan
−
1
(
b
a
c
o
s
x
)
+
c
(C)
1
a
b
cot
−
1
(
b
cos
x
a
)
+
c
\frac{1}{ab}\cot^{-1}\left(\frac{b\cos x}{a}\right) + c
ab
1
cot
−
1
(
a
b
c
o
s
x
)
+
c
(D)
1
a
b
cot
−
1
(
a
cos
x
b
)
+
c
\frac{1}{ab}\cot^{-1}\left(\frac{a\cos x}{b}\right) + c
ab
1
cot
−
1
(
b
a
c
o
s
x
)
+
c
Related theory
Inverse Trigonometric Functions
Trigonometric Functions
Integration Techniques
Integration by substitution
Integrals
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