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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
d
x
e
x
−
1
=
\displaystyle\int\frac{dx}{e^x-1}=
∫
e
x
−
1
d
x
=
(a)
ln
(
1
−
e
−
x
)
+
C
\ln(1-e^{-x})+C
ln
(
1
−
e
−
x
)
+
C
(b)
−
ln
(
1
−
e
x
)
+
C
-\ln(1-e^x)+C
−
ln
(
1
−
e
x
)
+
C
(c)
ln
(
e
x
−
1
)
+
C
\ln(e^x-1)+C
ln
(
e
x
−
1
)
+
C
(d) None of these
Related theory
Advanced Differentiation
Integration Techniques
Integration by Substitution
Integrals
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