Solve for in the interval .

MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

Solve sin⁡3x+2sin⁡3xcos⁡x=0\sin 3x + 2\sin 3x\cos x = 0 for xx in the interval [0,2π)[0,2\pi). (a) 0,  2π3,  π,  4π3,  2π0,\;\dfrac{2\pi}{3},\;\pi,\;\dfrac{4\pi}{3},\;2\pi (b) 0,  π3,  2π3,  π,  4π3,  5π30,\;\dfrac{\pi}{3},\;\dfrac{2\pi}{3},\;\pi,\;\dfrac{4\pi}{3},\;\dfrac{5\pi}{3} (c) 2π3,  4π3\dfrac{2\pi}{3},\;\dfrac{4\pi}{3} (d) 0,  π3,  2π3,  π,  3π2,  5π30,\;\dfrac{\pi}{3},\;\dfrac{2\pi}{3},\;\pi,\;\dfrac{3\pi}{2},\;\dfrac{5\pi}{3}

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