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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
sin
5
x
cos
4
x
d
x
=
\int \sin^5 x\,\cos^4 x\,dx =
∫
sin
5
x
cos
4
x
d
x
=
(a)
−
1
5
cos
5
x
+
2
7
cos
7
x
−
1
9
cos
9
x
+
c
-\frac{1}{5}\cos^5 x+\frac{2}{7}\cos^7 x-\frac{1}{9}\cos^9 x+c
−
5
1
cos
5
x
+
7
2
cos
7
x
−
9
1
cos
9
x
+
c
(b)
1
5
cos
5
x
+
2
7
cos
7
x
−
1
9
cos
9
x
+
c
\frac{1}{5}\cos^5 x+\frac{2}{7}\cos^7 x-\frac{1}{9}\cos^9 x+c
5
1
cos
5
x
+
7
2
cos
7
x
−
9
1
cos
9
x
+
c
(c)
1
5
cos
5
x
+
2
7
cos
7
x
+
1
9
cos
9
x
+
c
\frac{1}{5}\cos^5 x+\frac{2}{7}\cos^7 x+\frac{1}{9}\cos^9 x+c
5
1
cos
5
x
+
7
2
cos
7
x
+
9
1
cos
9
x
+
c
(d) None of these
Related theory
Integration Techniques
Integration by Substitution
Standard trigonometric integrals
Integration using trigonometric identities
Integrals
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