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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
tan
(
3
x
−
5
)
sec
(
3
x
−
5
)
d
x
=
\int \tan(3x-5)\sec(3x-5)\,dx =
∫
tan
(
3
x
−
5
)
sec
(
3
x
−
5
)
d
x
=
(A)
sec
(
3
x
−
5
)
+
c
\sec(3x-5) + c
sec
(
3
x
−
5
)
+
c
(B)
1
3
sec
(
3
x
−
5
)
+
c
\frac{1}{3}\sec(3x-5) + c
3
1
sec
(
3
x
−
5
)
+
c
(C)
tan
(
3
x
−
5
)
+
c
\tan(3x-5) + c
tan
(
3
x
−
5
)
+
c
(D) None of these
Related theory
Antiderivatives
Integration Techniques
Integration by Substitution
Integrals
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