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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
sin
x
sin
(
x
−
α
)
d
x
=
\int \frac{\sin x}{\sin(x - \alpha)}\,dx =
∫
s
i
n
(
x
−
α
)
s
i
n
x
d
x
=
(a)
x
cos
α
−
sin
α
log
sin
(
x
−
α
)
+
c
x\cos\alpha - \sin\alpha\,\log\sin(x - \alpha) + c
x
cos
α
−
sin
α
lo
g
sin
(
x
−
α
)
+
c
(b)
x
cos
α
+
sin
α
log
sin
(
x
−
α
)
+
c
x\cos\alpha + \sin\alpha\,\log\sin(x - \alpha) + c
x
cos
α
+
sin
α
lo
g
sin
(
x
−
α
)
+
c
(c)
x
sin
α
−
sin
α
log
sin
(
x
−
α
)
+
c
x\sin\alpha - \sin\alpha\,\log\sin(x - \alpha) + c
x
sin
α
−
sin
α
lo
g
sin
(
x
−
α
)
+
c
(d) None of these
Related theory
Trigonometric Identities
Trigonometric Functions
Integration Techniques
Standard trigonometric integrals
Integration using trigonometric identities
Integrals
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