The magnetic field of an electromagnetic wave is given by: B = 1.6 10^ -6 (2 10^7 z +…

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Waves Sound and Physical Optics · Waves Sound and Physical Optics

Problem

The magnetic field of an electromagnetic wave is given by: B⃗=1.6×10−6cos⁡(2×107z+6×1015t)(2i^+j^)Wbm2\vec{B} = 1.6 \times 10^{-6} \cos(2 \times 10^7 z + 6 \times 10^{15} t) (2\hat{i} + \hat{j}) \frac{Wb}{m^2} The associated electric field will be : (1) E⃗=4.8×102cos⁡(2×107z−6×1015t)(2i^+j^)Vm\vec{E} = 4.8 \times 10^2 \cos(2 \times 10^7 z - 6 \times 10^{15} t) (2\hat{i} + \hat{j}) \frac{V}{m} (2) E⃗=4.8×102cos⁡(2×107z−6×1015t)(−2j^+i^)Vm\vec{E} = 4.8 \times 10^2 \cos(2 \times 10^7 z - 6 \times 10^{15} t) (-2\hat{j} + \hat{i}) \frac{V}{m} (3) E⃗=4.8×102cos⁡(2×107z+6×1015t)(−i^+2j^)Vm\vec{E} = 4.8 \times 10^2 \cos(2 \times 10^7 z + 6 \times 10^{15} t) (-\hat{i} + 2\hat{j}) \frac{V}{m} (4) E⃗=4.8×102cos⁡(2×107z+6×1015t)(i^−2j^)Vm\vec{E} = 4.8 \times 10^2 \cos(2 \times 10^7 z + 6 \times 10^{15} t) (\hat{i} - 2\hat{j}) \frac{V}{m}

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