Consider the hypothetical reaction
816O+816O→1632S
Without performing numerical calculations, predict the energy change for this reaction on the basis of the binding-energy-per-nucleon curve.
(a) It absorbs energy because bringing two positively charged 16O nuclei together requires work to overcome Coulomb repulsion.
(b) It releases energy because the binding energy per nucleon decreases from 16O to 32S, and the difference appears as energy.
(c) It releases energy because 32S lies closer to the peak of the curve than 16O.
(d) It neither releases nor absorbs energy since the total number of nucleons and protons remains the same on both sides.