CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Introduction to Trigonometry · Introduction to Trigonometry

Problem

Find sin⁡2θ\sin 2\theta if θ=π8\theta=\dfrac{\pi}{8}. (a) 2−2\sqrt{2-\sqrt{2}} (b) 2+22\dfrac{\sqrt{2+\sqrt{2}}}{2} (c) 22\dfrac{\sqrt{2}}{2} (d) 2−22\dfrac{\sqrt{2-\sqrt{2}}}{2}

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