CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

∫sin⁡2xsin⁡4x+cos⁡4x dx=\displaystyle\int\frac{\sin2x}{\sin^4x+\cos^4x}\,dx= (a) cot⁡−1(tan⁡2x)+C\cot^{-1}(\tan^2x)+C (b) tan⁡−1(tan⁡2x)+C\tan^{-1}(\tan^2x)+C (c) cot⁡−1(cot⁡2x)+C\cot^{-1}(\cot^2x)+C (d) tan⁡−1(cot⁡2x)+C\tan^{-1}(\cot^2x)+C

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