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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
sin
2
x
sin
4
x
+
cos
4
x
d
x
=
\displaystyle\int\frac{\sin2x}{\sin^4x+\cos^4x}\,dx=
∫
sin
4
x
+
cos
4
x
sin
2
x
d
x
=
(a)
cot
−
1
(
tan
2
x
)
+
C
\cot^{-1}(\tan^2x)+C
cot
−
1
(
tan
2
x
)
+
C
(b)
tan
−
1
(
tan
2
x
)
+
C
\tan^{-1}(\tan^2x)+C
tan
−
1
(
tan
2
x
)
+
C
(c)
cot
−
1
(
cot
2
x
)
+
C
\cot^{-1}(\cot^2x)+C
cot
−
1
(
cot
2
x
)
+
C
(d)
tan
−
1
(
cot
2
x
)
+
C
\tan^{-1}(\cot^2x)+C
tan
−
1
(
cot
2
x
)
+
C
Related theory
Integration Techniques
Integration by Substitution
Integrals
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