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MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions
Problem If sin 3 θ − cos 3 θ sin θ − cos θ − cos θ 1 + cot 2 θ − 2 tan θ cot θ = − 1 \frac{\sin^3\theta-\cos^3\theta}{\sin\theta-\cos\theta}-\frac{\cos\theta}{\sqrt{1+\cot^2\theta}}-2\tan\theta\cot\theta=-1 s i n θ − c o s θ s i n 3 θ − c o s 3 θ − 1 + c o t 2 θ c o s θ − 2 tan θ cot θ = − 1 , where θ ∈ [ 0 , 2 π ] \theta\in[0,2\pi] θ ∈ [ 0 , 2 π ] , then
(1) θ ∈ ( 0 , π 2 ) ∖ { π 4 } \theta\in\left(0,\frac{\pi}{2}\right)\setminus\left\{\frac{\pi}{4}\right\} θ ∈ ( 0 , 2 π ) ∖ { 4 π }
(2) θ ∈ ( π 2 , π ) ∖ { 3 π 4 } \theta\in\left(\frac{\pi}{2},\pi\right)\setminus\left\{\frac{3\pi}{4}\right\} θ ∈ ( 2 π , π ) ∖ { 4 3 π }
(3) θ ∈ ( π , 3 π 2 ) ∖ { 5 π 4 } \theta\in\left(\pi,\frac{3\pi}{2}\right)\setminus\left\{\frac{5\pi}{4}\right\} θ ∈ ( π , 2 3 π ) ∖ { 4 5 π }
(4) θ ∈ ( 0 , π ) ∖ { π 4 , π 2 } \theta\in(0,\pi)\setminus\left\{\frac{\pi}{4},\frac{\pi}{2}\right\} θ ∈ ( 0 , π ) ∖ { 4 π , 2 π }
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