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Let and . Then is equal…
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
Let
I
1
=
∫
0
1
e
x
1
+
x
d
x
I_1=\int_0^1\frac{e^x}{1+x}\,dx
I
1
=
∫
0
1
1
+
x
e
x
d
x
and
I
2
=
∫
0
1
x
2
e
x
3
(
2
−
x
3
)
d
x
I_2=\int_0^1\frac{x^2}{e^{x^3}(2-x^3)}\,dx
I
2
=
∫
0
1
e
x
3
(
2
−
x
3
)
x
2
d
x
. Then
I
1
I
2
\frac{I_1}{I_2}
I
2
I
1
is equal to (1)
3
e
\frac{3}{e}
e
3
(2)
3
e
2
\frac{3}{e^2}
e
2
3
(3)
3
e
3e
3
e
(4)
1
3
e
\frac{1}{3e}
3
e
1
Related theory
Integration Techniques
Integration by Substitution
Integrals
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