What are the solutions to the equation above?

MATHEMATICS · Single correct · CBSE · Mathematics · Quadratic Equations · Quadratic Equations

Problem

100−121k2=0100-121k^2=0 What are the solutions to the equation above? (A) k=100121k=\frac{100}{121} (B) k=−100121k=-\frac{100}{121} and k=100121k=\frac{100}{121} (C) k=1011k=\frac{10}{11} (D) k=−1011k=-\frac{10}{11} and k=1011k=\frac{10}{11}

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