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Let , then…
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
Let
∫
f
(
ln
x
)
d
x
=
x
e
x
+
c
\int f(\ln x)\,dx=xe^x+c
∫
f
(
ln
x
)
d
x
=
x
e
x
+
c
, then
∫
f
(
x
)
⋅
e
x
1
+
e
x
d
x
\int \frac{f(x)\cdot e^x}{1+e^x}\,dx
∫
1
+
e
x
f
(
x
)
⋅
e
x
d
x
is (a)
e
e
x
+
c
e^{e^x}+c
e
e
x
+
c
(b)
ln
x
⋅
e
x
+
c
\ln x\cdot e^x+c
ln
x
⋅
e
x
+
c
(c)
e
e
x
⋅
e
x
+
c
e^{e^x}\cdot e^x+c
e
e
x
⋅
e
x
+
c
(d)
x
e
e
x
+
c
xe^{e^x}+c
x
e
e
x
+
c
Related theory
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