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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
cos
3
x
e
log
(
sin
x
)
d
x
\int\cos^3x\,e^{\log(\sin x)}\,dx
∫
cos
3
x
e
l
o
g
(
s
i
n
x
)
d
x
is equal to (a)
−
sin
4
x
4
+
C
-\frac{\sin^4x}{4}+C
−
4
s
i
n
4
x
+
C
(b)
−
cos
4
x
4
+
C
-\frac{\cos^4x}{4}+C
−
4
c
o
s
4
x
+
C
(c)
e
sin
x
4
+
C
\frac{e^{\sin x}}{4}+C
4
e
s
i
n
x
+
C
(d) None of these
Related theory
Antiderivatives
Integration Techniques
Integration by Substitution
Integrals
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