A curve is passing through origin

MATHEMATICS · Single correct · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

A curve g(x)=∫x27(1+x+x2)4(6x2+5x+4) dxg(x) = \int x^{27} (1+x+x^2)^4 (6x^2+5x+4)\,dx is passing through origin. Then (a) g(1)=377g(1) = \frac{3^7}{7} (b) g(1)=277g(1) = \frac{2^7}{7} (c) g(−1)=17g(-1) = \frac{1}{7} (d) g(−1)=3714g(-1) = \frac{3^7}{14}

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