Solve for using the null factor law:

MATHEMATICS · Multi-part · AoPS · Mathematics · Quadratic Equations - Part 1 · Quadratic Equations - Part 1

Problem

Solve for xx using the null factor law: (1) x(x−5)=0x(x - 5) = 0 (2) 2x(x+3)=02x(x + 3) = 0 (3) (x+1)(x−3)=0(x + 1)(x - 3) = 0 (4) (x−4)(x+7)=0(x - 4)(x + 7) = 0 (5) 3x(7−x)=03x(7 - x) = 0 (6) −2x(x+1)=0-2x(x + 1) = 0 (7) 4(x+6)(2x−3)=04(x + 6)(2x - 3) = 0 (8) (2x+1)(2x−1)=0(2x + 1)(2x - 1) = 0 (9) 11(x+2)(x−7)=011(x + 2)(x - 7) = 0 (10) −6(x−5)(3x+2)=0-6(x - 5)(3x + 2) = 0 (11) x2(x+5)=0x^2(x + 5) = 0 (12) 4(5−x)2=04(5 - x)^2 = 0 (13) −3(3x−1)2=0-3(3x - 1)^2 = 0 (14) x(x+1)(x−2)=0x(x + 1)(x - 2) = 0 (15) (x−1)(x+2)(x−3)=0(x - 1)(x + 2)(x - 3) = 0 (16) 3(x+2)(x+4)(2x−1)=03(x + 2)(x + 4)(2x - 1) = 0

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